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					@ -32,13 +32,16 @@ The $n means the pool rewards $t times the expected number of shares, each time
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					So each share will be paid appoximately $ot of it's expected value, in each block it gets a reward,<br> | 
				
			
			
		
	
		
			
				
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					but each share is also expected, on average, to be rewarded $t times in blocks found after the share is submitted to the pool.<br> | 
				
			
			
		
	
		
			
				
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					i.e. if pool luck was always 100% then each share is expected to be rewarded $t times.<br><br> | 
				
			
			
		
	
		
			
				
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					If pool luck is better than 100%, then the average share reward wil be better than $t times.<br> | 
				
			
			
		
	
		
			
				
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					If pool luck is better than 100%, then the average share reward will be better than $t times.<br> | 
				
			
			
		
	
		
			
				
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					If pool luck is lower than 100%, then the average share reward will be less than $t times.<br><br> | 
				
			
			
		
	
		
			
				
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					<span class=hdr>What's a shift?</span></br><br> | 
				
			
			
		
	
		
			
				
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					When your miner sends shares to the pool, the shares are not stored individually, but rather summarised into shifts.<br> | 
				
			
			
		
	
		
			
				
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					Shifts are ~50min or less in length, however, when we find any pool blocks the current shift ends early,<br> | 
				
			
			
		
	
		
			
				
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					at the point the block was found.<br> | 
				
			
			
		
	
		
			
				
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					Shifts are ~50min or less in length.<br> | 
				
			
			
		
	
		
			
				
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					Aproximately every 30s, the pool generates new work and sends that to all the miners.<br> | 
				
			
			
		
	
		
			
				
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					The pool also sends new work every time a block is found on the Bitcoin network.<br> | 
				
			
			
		
	
		
			
				
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					A shift summarises all the shares submitted to the pool for 100 work changes.<br> | 
				
			
			
		
	
		
			
				
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					However, when we find pool blocks, the current shift ends at the work in which the block was found.<br> | 
				
			
			
		
	
		
			
				
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					A ckpool restart will also end the current shift and start a new one.<br><br> | 
				
			
			
		
	
		
			
				
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					<span class=hdr>So, what's the $n value?</span><br><br> | 
				
			
			
		
	
	
		
			
				
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